let x#y=(x^2)/y for all values of x and y where y does not equal 0. Find all values of x such that x#3=9. Thanks so much!

WhichWitchIsWhich
Nov 3, 2017

#1**+2 **

So a function (?) question. Also, it doesn't specify whether it should be an integer or not. I'm guessing you mean an integer.

We are told that \(x = x\) and \(y=3\). Plug it in.

\(x\)#\(3\)\(=\dfrac{x^2}{3}\)

Also, \(x\)#\(3=9\). Plug that in too.

\(9= \dfrac{x^2}{3}\) . Now multiply both sides by 3 to get rid of the fraction...

\(27=x^2\). So \(x = \sqrt{27}\). It is also equal to \(- \sqrt{27}\). THAT DOES NOT LOOK LIKE A NICE NUMBER.

~~Unless I made a mistake which is 100% possible. ~~

Vivien
Nov 4, 2017