We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

let x#y=(x^2)/y for all values of x and y where y does not equal 0. Find all values of x such that x#3=9. Thanks so much!

WhichWitchIsWhich Nov 3, 2017

#1**+2 **

So a function (?) question. Also, it doesn't specify whether it should be an integer or not. I'm guessing you mean an integer.

We are told that \(x = x\) and \(y=3\). Plug it in.

\(x\)#\(3\)\(=\dfrac{x^2}{3}\)

Also, \(x\)#\(3=9\). Plug that in too.

\(9= \dfrac{x^2}{3}\) . Now multiply both sides by 3 to get rid of the fraction...

\(27=x^2\). So \(x = \sqrt{27}\). It is also equal to \(- \sqrt{27}\). THAT DOES NOT LOOK LIKE A NICE NUMBER.

~~Unless I made a mistake which is 100% possible. ~~

Vivien Nov 4, 2017