Entered | Answer Preview | Result | Messages |
---|---|---|---|
(r^2)*[e^(r*x)]-3*r*[e^(r*x)]-40*[e^(r*x)] | r^2*e^(rx)-3*r*e^(rx)-40*e^(rx) | correct | |
(e^rx)*[(r-8)*(r+5)] | | incorrect | Powers must be either 0 or 1 |
-5, 8 | −5,8 | correct |
Hello. What are we going to find to help you?
And great answer in the negative 1 and negative 2 question.
i mea a and c are correct but when i simplify the b as (e^rx)*[(r-8)*(r+5)] i gotta do something else i think
y"−3y′−40y=0.Tryy=erxy′=rerxy"=r2erxThe question becomesr2erx−3rerx−40erx=0erx(r2−3r−40)=0erx(r−8)(r+5)=0The only solutions to this are r=8andr=−5
Dragon, this stuff is way over the top of your head. Sorry mate.
Milkshake,
Does that help?
But great answer, though. Keep it up, or lose the grand war of Camelot.