+0  
 
+3
3608
9
avatar+102 
Entered Answer Preview Result Messages
(r^2)*[e^(r*x)]-3*r*[e^(r*x)]-40*[e^(r*x)]  r^2*e^(rx)-3*r*e^(rx)-40*e^(rx) correct  
(e^rx)*[(r-8)*(r+5)]
                                                             
incorrect Powers must be either 0 or 1
-5, 8
−5,8
correct  

 

At least one of the answers above is NOT correct.

 

 
 
 
(1 pt) Let y′′−3y′−40y=0.
  1. Try a solution of the form y=erx, for some unknown constant r, by substituting it into the differential equation. 
                 r^2*e^(rx)-3*r*e^(rx)-40*e^(rx)=0.

  2. Simplify and factor your equation in the previous part as much as possible. Be sure to divide out any factors guaranteed to be nonzero. 
    ______________=0.

  3. Find all values of r such that y=erx satisfies the differential equation. If there is more than one correct answer, enter your answers as a comma separated list. 
                 r= -5,8
 Sep 9, 2014

Best Answer 

 #3
avatar+118608 
+8

$$\\y"-3y'-40y=0.\\\\
Try \\
y=e^{rx}\qquad y'=re^{rx} \qquad y"=r^2e^{rx}\\\\
\mbox{The question becomes}\\\\
r^2e^{rx}-3re^{rx}-40e^{rx}=0\\\\
e^{rx}(r^2-3r-40)=0\\\\
e^{rx}(r-8)(r+5)=0\\\\
\mbox{The only solutions to this are }
r=8\;\; and\;\; r=-5$$

.
 Sep 9, 2014
 #1
avatar+8261 
0

Hello. What are we going to find to help you? 

And great answer in the negative 1 and negative 2 question.

 Sep 9, 2014
 #2
avatar+102 
+3

i mea a and c are correct but when i simplify the b as (e^rx)*[(r-8)*(r+5)]  i gotta do something else i think

 Sep 9, 2014
 #3
avatar+118608 
+8
Best Answer

$$\\y"-3y'-40y=0.\\\\
Try \\
y=e^{rx}\qquad y'=re^{rx} \qquad y"=r^2e^{rx}\\\\
\mbox{The question becomes}\\\\
r^2e^{rx}-3re^{rx}-40e^{rx}=0\\\\
e^{rx}(r^2-3r-40)=0\\\\
e^{rx}(r-8)(r+5)=0\\\\
\mbox{The only solutions to this are }
r=8\;\; and\;\; r=-5$$

Melody Sep 9, 2014
 #4
avatar+118608 
+3

Dragon, this stuff is way over the top of your head.  Sorry mate.

 

Milkshake,

Does that help?

 Sep 9, 2014
 #5
avatar+126 
+3

this is so confusing I can't help and hey guys.

 Sep 9, 2014
 #6
avatar+102 
+3

i found the solution for my own!)

(e^0)*[(r-8)*(r+5)] 

http://i62.tinypic.com/6iu26h.jpg

 Sep 9, 2014
 #7
avatar+126 
+3

so you searched it?

 Sep 9, 2014
 #8
avatar+8261 
0

I could think of it on top on my head...

Homework Help

           

 Sep 9, 2014
 #9
avatar+8261 
0

But great answer, though. Keep it up, or lose the grand war of  Camelot.

 Sep 9, 2014

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