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Let

\(\begin{align*} A_0 &= 6 \\ A_1 &= 5 \\ A_n &= A_{n - 1} + A_{n - 2} \; \textrm{for} \; n \geq 2. \end{align*} \)

There is a unique ordered pair (c,d) such that \(c\phi^n + d\widehat{\phi}^n\) is the closed form for sequence A_n. Find c using the Fibonacci and Lucas number sequences.

 May 30, 2020
 #1
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From the Fibonacci and Lucas formula, c = (7 + 2*sqrt(5))/2.

 May 31, 2020
 #2
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apologies, that's incorrect :(

Guest May 31, 2020

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