+46 Suppose you drop a ball from a window 15 meters above the ground. The ball bounces to 60% of its previous height with each bounce. What is the total number of meters (rounded to the nearest tenth) the ball travels between the time it is dropped and the 10th bounce?
A.) 37.3 meters
B.) 378.6 meters
C.) 59.5 meters
D.) 63.4 meters
+118680 -15 +(30 + 18+ ....... )
-15+( sum of a GP with a=30, r=0.6 n=10)
\(-15+\frac{a(1-r^n)}{1-r}\\ =-15+\frac{30*(1-0.6^{10})}{1-0.6}\\ =-15+\frac{30*(1-0.6^{10})}{0.4}\\\)
-15+(30*(1-0.6^10))/0.4 = 59.5465 m
This is to the 10th bounce but it does not include the 10th bounce
Feel free to ask questions :)
