+0  
 
0
89
1
avatar+46 

Suppose you drop a ball from a window 15 meters above the ground. The ball bounces to 60% of its previous height with each bounce. What is the total number of meters (rounded to the nearest tenth) the ball travels between the time it is dropped and the 10th bounce?

 

A.) 37.3 meters

B.) 378.6 meters

C.) 59.5 meters

D.) 63.4 meters

Redsox123  May 11, 2017
Sort: 

1+0 Answers

 #1
avatar+89843 
+1

-15 +(30 + 18+ ....... )

 

-15+( sum of a GP with a=30, r=0.6 n=10)

 

\(-15+\frac{a(1-r^n)}{1-r}\\ =-15+\frac{30*(1-0.6^{10})}{1-0.6}\\ =-15+\frac{30*(1-0.6^{10})}{0.4}\\\)

 

-15+(30*(1-0.6^10))/0.4 = 59.5465 m

 

This is to the 10th bounce but it does not include the 10th bounce

 

Feel free to ask questions :)

Melody  May 11, 2017

19 Online Users

avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details