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lim x2 + x3 - x / x4 - x2 + 1
x--> infinity
 Nov 1, 2013
 #1
avatar+118652 
0
http://en.wikipedia.org/wiki/L'H%C3%B4pital's_rule

Use L'Hopital's Rule

This is not exactly the question you wrote, but I think it is what you intended.
If I got the intention wrong then I am sorry.

lim [x 2 + x 3 - x] / [x 4 - x 2 +1]
x--> infinity

= lim [2x + 3x 2 - 1] / [4x 3 - 2x]
x--> infinity

= lim [2 + 6x ] / [12x 2 - 2 ]
x--> infinity

= lim 6/(24x)
x--> infinity

=0
 Nov 1, 2013
 #2
avatar+3146 
0
[input]lim( (x^2 + x^3 - x) / (x^4 - x^2 + 1), x=inf )[/input]
 Nov 1, 2013

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