+0  
 
0
156
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avatar+956 

I plugged in 1 for the f(x) I got: 

\( 1-3x \over 1+x^2\)

As it approaches 0 \( 1-0 \over 1+0\)

Which simplifies to 1 

 

I feel this is like very wrong :| 

Julius  Feb 19, 2018
 #1
avatar+3270 
0

 

If \(\underset{x\rightarrow0}{lim}f(x)=1\), we have not indefinite case \(\frac{0}{0}\), so we have not a real problem, and we can't use for example the l'Hospital rule . We must have \(\underset{x\rightarrow0}{lim}f(x)=0.\)

tertre  Feb 19, 2018
edited by tertre  Feb 19, 2018
 #2
avatar+956 
0

Umm, so what do we do? 

Julius  Feb 20, 2018

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