I plugged in 1 for the f(x) I got:
1−3x1+x2
As it approaches 0 1−01+0
Which simplifies to 1
I feel this is like very wrong :|
If limx→0f(x)=1, we have not indefinite case 00, so we have not a real problem, and we can't use for example the l'Hospital rule . We must have limx→0f(x)=0.
Umm, so what do we do?