+0  
 
0
79
2
avatar+910 

I plugged in 1 for the f(x) I got: 

\( 1-3x \over 1+x^2\)

As it approaches 0 \( 1-0 \over 1+0\)

Which simplifies to 1 

 

I feel this is like very wrong :| 

Julius  Feb 19, 2018
Sort: 

2+0 Answers

 #1
avatar+2595 
0

 

If \(\underset{x\rightarrow0}{lim}f(x)=1\), we have not indefinite case \(\frac{0}{0}\), so we have not a real problem, and we can't use for example the l'Hospital rule . We must have \(\underset{x\rightarrow0}{lim}f(x)=0.\)

tertre  Feb 19, 2018
edited by tertre  Feb 19, 2018
 #2
avatar+910 
0

Umm, so what do we do? 

Julius  Feb 20, 2018

29 Online Users

avatar
avatar
avatar
avatar
avatar
New Privacy Policy (May 2018)
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  Privacy Policy