Limit as x approaches 9 and the equation is (3-rootx)/9-x how do we solve this limit?
One way as follows:
\(\frac{3-\sqrt x}{9-x}=\frac{3-\sqrt x}{(3-\sqrt x)(3+\sqrt x)}=\frac{1}{3+\sqrt x}\)
Hence limit as x tends to 9 is 1/6
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