Line 1 represents the graph of 3x + 4y = -14. Line 2 passes through the point (-5,7), and is perpendicular to line 1. If line 2 represents the graph of y=mx +b, then find m+b.
Write 3x+4y=-14 in slope intercept form:
The line perpendicular to it must have slope of 4/3. So we have y=4/3x+b. We plug in the given point (-5, 7) to solve for b.
m+b is 4/3+41/3=45/3=15.