Line 1 represents the graph of 3x + 4y = -14. Line 2 passes through the point (-5,7), and is perpendicular to line 1. If line 2 represents the graph of y=mx +b, then find m+b.
Write 3x+4y=-14 in slope intercept form:
3x+4y=-14
4y=-3x-14
y=-3/4x-14/4
The line perpendicular to it must have slope of 4/3. So we have y=4/3x+b. We plug in the given point (-5, 7) to solve for b.
7=4/3(-5)+b
7=-20/3+b
b=41/3
m+b is 4/3+41/3=45/3=15.