+0  
 
0
240
1
avatar

Find the point with x-coordinate -92 on the line through (26, 1052) and (-53,-1950).

Guest Apr 17, 2017

Best Answer 

 #1
avatar+7266 
+2

The slope of a line that passes through (26 , 1052) and (-53 , -1950) = \(\frac{\text{change in y's}}{\text{change in x's}}=\frac{1052-(-1950)}{26-(-53)}=\frac{3002}{79}=38\)

 

The equation of this line is

(y - 1052) = 38(x - 26)

y = 38x - 988 + 1052

y = 38x + 64

 

Now, just plug in -92 for x and solve for y.

y = 38(-92) + 64 = -3496 + 64 = -3432

 

So, the point with an x-coordinate of -92 is : (-92 , -3432)

hectictar  Apr 18, 2017
 #1
avatar+7266 
+2
Best Answer

The slope of a line that passes through (26 , 1052) and (-53 , -1950) = \(\frac{\text{change in y's}}{\text{change in x's}}=\frac{1052-(-1950)}{26-(-53)}=\frac{3002}{79}=38\)

 

The equation of this line is

(y - 1052) = 38(x - 26)

y = 38x - 988 + 1052

y = 38x + 64

 

Now, just plug in -92 for x and solve for y.

y = 38(-92) + 64 = -3496 + 64 = -3432

 

So, the point with an x-coordinate of -92 is : (-92 , -3432)

hectictar  Apr 18, 2017

37 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.