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The equation of the line that passes through the points (-2,0) and (0,8) can be expressed in the form y=mx+b. What is the value of m+b?

 Jan 20, 2021

Best Answer 

 #1
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+1

calculate the slope   (y--y2)/(x1-x2)           (8-0)/(0 - - 2) = 4

use one point to produce line the in point-slope form

 

(y-8) = 4(x-0)          re-arramnge to y = mx+b form

y - 8 = 4x

y = 4x+8       m = 4   b = 8      

 Jan 20, 2021
 #1
avatar
+1
Best Answer

calculate the slope   (y--y2)/(x1-x2)           (8-0)/(0 - - 2) = 4

use one point to produce line the in point-slope form

 

(y-8) = 4(x-0)          re-arramnge to y = mx+b form

y - 8 = 4x

y = 4x+8       m = 4   b = 8      

Guest Jan 20, 2021
 #2
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@Guest: The problem is asking what is m+b, not m and b. In addition of your post as you stated that m is 4 and b is 8, 4+8=12

 Jan 21, 2021
 #3
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Exactly.......I was under the impression that the poster was able to add m + b to complete the answer,  Knucklehead.

Guest Jan 21, 2021

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