Linear Equation problem... help?

2m÷5+3=7(4m-3)

\(2m\div 5+3=7(4m-3)\\ \frac{2m}{5}+3=7(4m-3)\\\)

Here is a start.

1) Expand the brackets on the RHS

2) Multiply both sides by 5. that will get rid of the fraction.

3) Subtract 2m from BOTH sides

then see if you can work out how to finish.

Remember that if you do something to one side you MUST do it to the other side as well

The equation must stay balanced.

Give that a go and let us know how you get on. 

There are different ways of do questions like this. 

\(2m\div 5+3=7(4m-3)\\ \frac{2m}{5}+3=7(4m-3)\\ \)

Expand the brackets

\(\frac{2m}{5}+3=28m-21\\ \text{Multiply both sides by 5 to get rid of the fraction}\\ 5\left(\frac{2m}{5}+3\right)=5(28m-21)\\ \text{simplify both sides seperately}\\ 5*\frac{2m}{5}+5*3=5*28m-5*21\\ 2m+15=140m-105\\ \)

NOW the idea is to get all the lots of letters all on the same side, you have  2m on one sides and 140m on the other side.

I want to get rid off the 2m of the left side SO I have TAKE IT AWAY 

but what i do to one side I must do to the other sides as well because the equation must sty balanced!

\(2m+15-2m=140m-105-2m\\ simplify\\ 15=138m-105\\ \)

Now I neede to get all the numbers without letters onto the same side.

So I will add 105 to both sides.

\(15+105=138m-105+105\\ simplify\\ 120=138m\)

Only now do I want to seperate the 138 from the m

138m = 138*m

the opposite of times is divide

so   138m divided by 138 = m

also divide is the same a fraction line

so

\(138m\div138 = \frac{138m}{138}=m\)

SO I need to divide both sides by 138

\(\frac{120}{138}=\frac{138m}{138}\\ \frac{120}{138}=m\\ m=\frac{120}{138}\\ m=\frac{20}{23}\)

It is better to keep it as a fraction.