Find the equation of the line graphed below. Write the equation in the form y=mx+b and identify m and b.
The slope appears to be 8/3, and the y-intercept appears to be 1. So the equation is y=8/3x+1.
How did you get 8/3 as the gradient here?
This is incorrect as the gradient is 1/4
Using rise/run, it can be seen that the gradient of this line is 1/4.
The labelled y intercept is the value of b, thus 1
Therefore the equation of this line is equal to:
y=1/4x + 1
*Checked in online graphing tool*