Linear equations

3x-2(5x-3)=7 => 3χ-2*5χ+2*3=7 => 3χ-10χ+6=7 => 7χ=7-6 => 7χ/7=1/7 =>χ=1/7

I am just learning this stuff and of course am confused...

I do not under stand your 3 step 7x=7-6

could you please explain to me how you got that equation from 3x-10x+6=7

Like I said, this is a learning process...so forgive me if I sound dumb

sddao:

I am just learning this stuff and of course am confused...

I do not under stand your 3 step 7x=7-6

could you please explain to me how you got that equation from 3x-10x+6=7

Like I said, this is a learning process...so forgive me if I sound dumb

You can subtract or add anything on either side, as long as you add it on the other side as well.

So he took 3x-10x+6=7 => minus 6, so it becomes 3x-10x = 7-6.
3x-10x = 7x and 7-6 = 1 .... so 7x = 1. To get x, you divide by the number of x's.
7x / 7 = x, 1 / 7 = 1/7.

x = 1/7

THIS IS WRONG the answer is 3x-6=7 which become 3x = 7+6 which is 3x= 13 so X = 13/3 = 4.33333333333333(RECURRING)333333333

[input]3x-2(5x-3)=7[/input]

3x-2(5x-3)=7
3x-(2*5x-2*3)=7
3x-2*5x+6=7 | -6
3x-10x=1
-7x=1 | /-7
x=-1/7

3x-2(5x-3)=7
=3x-10x+6=7 I-6
=3x-10x =1
=-7x =1I:-7
=x =-1/7