I keep getting the wrong answer on this one.

Find the distance between the x-intercept and the y-intercept of the graph of the equation 3x - 7y = 21 + 2x - 5y.

sandwich Apr 24, 2023

#1**0 **

*Find the distance between the x-intercept and the y-intercept of the graph of the equation 3x - 7y = 21 + 2x - 5y*.

3x - 7y = 21 + 2x - 5y

Combine like terms. –7y + 5y = 2x – 3x + 21

–2y = –x + 21

Multiply both sides by –1

this isn't necessary but it

makes it easy to work with.

Easier for me, anyway, LOL. 2y = x – 21

Set y = 0 and solve for x x = 21 That's your x-intercept.

Set x = 0 and solve for y y = –10**.**5 That's your y-intercept.

Those are the values of the two legs of a right triangle, with the origin being the right angle.

If you draw it on a graph, it's obvious.

The line between the x- and y- intercepts is the hypotenuse of that right triangle.

Pythagoras' Theorem c^{2} = (21)^{2} + (–10**.**5)^{2}

c^{2} = 441 + 110**.**25 = 551**.**25

I used my calculator to

get this square root. c = **23.48**

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Guest Apr 24, 2023