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a line that is perpendicular to 2x-4y+9=0 and same x-intercept as 6x-10y+24=0

 Jan 30, 2017

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 #2
avatar+21681 
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Picture of all of this:

 

 Jan 30, 2017
 #1
avatar+21681 
+5

2x-4y+9=0    is the same as    y= 1/2 x +9/4      slope is 1/2   perindicular slope is  - (1/ (1/2) ) = -2

 

so our line to construct will look like   y = -2x + b

 

now  6x-10y +24= 0   has x-intercept when y=0      at that point x= -4     so our line under construction must pass through this point   -4,0  

Substitute this point into our line under construction:       

0=-2(-4) + b    results in b=-8    

so our line is    y =  -2x -8              or      -2x -8 -y = 0         Perpindicular to the first line and passing thru (-4,0)

 Jan 30, 2017
 #2
avatar+21681 
+5
Best Answer

Picture of all of this:

 

ElectricPavlov  Jan 30, 2017

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