a line that is perpendicular to 2x-4y+9=0 and same x-intercept as 6x-10y+24=0
2x-4y+9=0 is the same as y= 1/2 x +9/4 slope is 1/2 perindicular slope is - (1/ (1/2) ) = -2
so our line to construct will look like y = -2x + b
now 6x-10y +24= 0 has x-intercept when y=0 at that point x= -4 so our line under construction must pass through this point -4,0
Substitute this point into our line under construction:
0=-2(-4) + b results in b=-8
so our line is y = -2x -8 or -2x -8 -y = 0 Perpindicular to the first line and passing thru (-4,0)