literal equations

Question

+2

1910

1

+470

y=mx+b (solve for b)

A=h(b+c) (solve for b)

A=4r^2 (solve for r^2)

7x-y=14 (solve for x)

R= (E/i) (solve for i)

A= (r/2L) (solve for L)

Neptune Oct 19, 2017

+9488

+2

Best Answer

Solve for b .
y = mx + b		Subtract mx from both sides of the equation.
y - mx = b

Solve for b .
A = h(b + c)		Divide both sides of the equation by h .
A / h = b + c		Subtract c from both sides of the equation.
A / h - c = b

Solve for r² .
A = 4r²		Divide both sides of the equation by 4 .
A / 4 = r²

Solve for x .
7x - y = 14		First add y to both sides. See if you can figure the rest out.

Solve for i .
R = (E / i)		Multiply both sides of the equation by i .
i * R = E		Divide both sides of the equation by R.
i = E / R

Solve for L .		Using this as the equation A = $\frac{r}2$ L ,
A = $\frac{r}2$ L		multiply both sides by $\frac2r$ .
$\frac2r$ * A = $\frac{2}{r}$ * $\frac{r}{2}$ * L
$\frac{2A}{r}$ = L		If you meant for the equation to be A = $\frac{r}{2L}$ , then it is different!

hectictar Oct 20, 2017

hectictar · Answer 1 · 2017-10-20T12:16:54

Solve for b .
y = mx + b		Subtract mx from both sides of the equation.
y - mx = b

Solve for b .
A = h(b + c)		Divide both sides of the equation by h .
A / h = b + c		Subtract c from both sides of the equation.
A / h - c = b

Solve for r² .
A = 4r²		Divide both sides of the equation by 4 .
A / 4 = r²

Solve for x .
7x - y = 14		First add y to both sides. See if you can figure the rest out.

Solve for i .
R = (E / i)		Multiply both sides of the equation by i .
i * R = E		Divide both sides of the equation by R.
i = E / R

Solve for L .		Using this as the equation A = $\frac{r}2$ L ,
A = $\frac{r}2$ L		multiply both sides by $\frac2r$ .
$\frac2r$ * A = $\frac{2}{r}$ * $\frac{r}{2}$ * L
$\frac{2A}{r}$ = L		If you meant for the equation to be A = $\frac{r}{2L}$ , then it is different!