y=mx+b (solve for b)
A=h(b+c) (solve for b)
A=4r^2 (solve for r^2)
7x-y=14 (solve for x)
R= (E/i) (solve for i)
A= (r/2L) (solve for L)
Solve for b . | ||
y = mx + b | Subtract mx from both sides of the equation. | |
y - mx = b | ||
Solve for b . | ||
A = h(b + c) | Divide both sides of the equation by h . | |
A / h = b + c | Subtract c from both sides of the equation. | |
A / h - c = b | ||
Solve for r2 . | ||
A = 4r2 | Divide both sides of the equation by 4 . | |
A / 4 = r2 | ||
Solve for x . | ||
7x - y = 14 | First add y to both sides. See if you can figure the rest out. | |
Solve for i . | ||
R = (E / i) | Multiply both sides of the equation by i . | |
i * R = E | Divide both sides of the equation by R. | |
i = E / R | ||
Solve for L . | Using this as the equation A = \(\frac{r}2\)L , | |
A = \(\frac{r}2\)L | multiply both sides by \(\frac2r\) . | |
\(\frac2r\) * A = \(\frac{2}{r}\) * \(\frac{r}{2}\) * L | ||
\(\frac{2A}{r}\) = L | If you meant for the equation to be A = \(\frac{r}{2L}\) , then it is different! |
Solve for b . | ||
y = mx + b | Subtract mx from both sides of the equation. | |
y - mx = b | ||
Solve for b . | ||
A = h(b + c) | Divide both sides of the equation by h . | |
A / h = b + c | Subtract c from both sides of the equation. | |
A / h - c = b | ||
Solve for r2 . | ||
A = 4r2 | Divide both sides of the equation by 4 . | |
A / 4 = r2 | ||
Solve for x . | ||
7x - y = 14 | First add y to both sides. See if you can figure the rest out. | |
Solve for i . | ||
R = (E / i) | Multiply both sides of the equation by i . | |
i * R = E | Divide both sides of the equation by R. | |
i = E / R | ||
Solve for L . | Using this as the equation A = \(\frac{r}2\)L , | |
A = \(\frac{r}2\)L | multiply both sides by \(\frac2r\) . | |
\(\frac2r\) * A = \(\frac{2}{r}\) * \(\frac{r}{2}\) * L | ||
\(\frac{2A}{r}\) = L | If you meant for the equation to be A = \(\frac{r}{2L}\) , then it is different! |