y=mx+b (solve for b)

A=h(b+c) (solve for b)

A=4r^2 (solve for r^2)

7x-y=14 (solve for x)

R= (E/i) (solve for i)

A= (r/2L) (solve for L)

Neptune Oct 19, 2017

#1**+2 **

Solve for b . | ||

y = mx + b | Subtract mx from both sides of the equation. | |

y - mx = b | ||

Solve for b . | ||

A = h(b + c) | Divide both sides of the equation by h . | |

A / h = b + c | Subtract c from both sides of the equation. | |

A / h - c = b | ||

Solve for r^{2} . | ||

A = 4r^{2} | Divide both sides of the equation by 4 . | |

A / 4 = r^{2} | ||

Solve for x . | ||

7x - y = 14 | First add y to both sides. See if you can figure the rest out. | |

Solve for i . | ||

R = (E / i) | Multiply both sides of the equation by i . | |

i * R = E | Divide both sides of the equation by R. | |

i = E / R | ||

Solve for L . | Using this as the equation A = \(\frac{r}2\)L , | |

A = \(\frac{r}2\)L | multiply both sides by \(\frac2r\) . | |

\(\frac2r\) * A = \(\frac{2}{r}\) * \(\frac{r}{2}\) * L | ||

\(\frac{2A}{r}\) = L | If you meant for the equation to be A = \(\frac{r}{2L}\) , then it is different! |

hectictar Oct 20, 2017

#1**+2 **

Best Answer

Solve for b . | ||

y = mx + b | Subtract mx from both sides of the equation. | |

y - mx = b | ||

Solve for b . | ||

A = h(b + c) | Divide both sides of the equation by h . | |

A / h = b + c | Subtract c from both sides of the equation. | |

A / h - c = b | ||

Solve for r^{2} . | ||

A = 4r^{2} | Divide both sides of the equation by 4 . | |

A / 4 = r^{2} | ||

Solve for x . | ||

7x - y = 14 | First add y to both sides. See if you can figure the rest out. | |

Solve for i . | ||

R = (E / i) | Multiply both sides of the equation by i . | |

i * R = E | Divide both sides of the equation by R. | |

i = E / R | ||

Solve for L . | Using this as the equation A = \(\frac{r}2\)L , | |

A = \(\frac{r}2\)L | multiply both sides by \(\frac2r\) . | |

\(\frac2r\) * A = \(\frac{2}{r}\) * \(\frac{r}{2}\) * L | ||

\(\frac{2A}{r}\) = L | If you meant for the equation to be A = \(\frac{r}{2L}\) , then it is different! |

hectictar Oct 20, 2017