+83 Lizzie has a strange deck of number cards that contains cards labeled 2 through 9 in three different colors (red, blue, and green).
(a) In how many ways can she draw one card from each color so that the sum of all the cards is 10?
(b) In how many ways can she draw one card from each color so that the sum of all the cards is 20?
Colors matter!
You have 9 - 2 + 1 = 8 cards with red, blue and green colors. How are the 3 colors distributed among the 8 cards?
Or, should your cards be labeled 1 through 9?.
Here is a hint for anybody who wants to try it:
You can only make the sum of 10 in four different ways as follows:
6 + 2 + 2 = 10 - permutations =3! / 2! =3
5 + 3 + 2 = 10 - .................... =3! = 6
4 + 4 + 2 = 10 - .................... =3! / 2! =3
4 + 3 + 3 = 10 - .................... =3! / 2! =3
And you can only make the sum of 20 in eight different ways as follows:
9 + 9 + 2 = 20 - permutations = 3! / 2! =3
9 + 8 + 3 = 20 - ..................... = 3! =6
9 + 7 + 4 = 20 - ..................... = 3! =6
9 + 6 + 5 = 20 - ..................... = 3! =6
8 + 8 + 4 = 20 - ..................... = 3! / 2! =3
8 + 7 + 5 = 20 - ..................... = 3! =6
8 + 6 + 6 = 20 - ..................... =3! / 2! =3
7 + 7 + 6 = 20 - ..................... =3! / 2! =3
That is as far as I go!!!.
+83 that's I thought I should do but I'm not sure if there's a better way
+83 I think its a) 90 and b) 216
Please correct me and show me how to do this problem if I'm wrong
I'm thinking that each 3-number combination for making up a 10 should be:
3^3 x 4 =108 ways.
And each 3-number combination for making up a 20 should be:
3^3 x 8 =216 ways.
+83 This was what I was thinking for (a):
There are 3!*(3+6+3+3) ways so it's 90.
(3! is for the colors, 3+6+3+3 is the number of ways the sum is 10)
So how am I supposed to do it then?
The way I came up with 108 and 216 is as follows:
Take the first combination to make up a 10: 6 + 2 + 2 =10. But the first 6 comes in 3 colors: red, blue, green.
The second 2 also comes in 3 colors: red, blue, green. The same thing goes for the third 2. So, we have a combination of 3 x 3 x 3 = 27 possible ways to make up 6 + 2 + 2 =10. And this should apply to the other 3 remaining combinations of 10. So, 27 x 4 =108 ways of making up a 10.
Exactly the same reasoning applies to making up the 20s, 3 x 3 x 3 x 8 =216 ways.
That is my best guess!.
