When I evaluate ln(1/e) it comes out as -1, I'm confused how as the steps don't make sense to me. Do you use logb(m/n)=logbM-logbN? I thought ln and e would cancel and you'd be left with -1.
\(\dfrac 1 e = e^{-1}\\ \ln\left(e^{-1}\right) = -1\\ \ln\left(\dfrac 1 e\right) = -1\)
Remember that 1 / e = e^(-1)
So.....
ln (1 / e) = ln e^(-1)
And by a log property..... ln a^b = b * ln a
So
ln e^(-1) = -1 * ln e
But ln e = 1 .....so
(-1) * (1) = -1
