HI!
I have a few problems to solve involving logs. Here's one:
I have to write in one log the following:
2log base 5 (3) - 3log base 5 (2)
So far I went like this:
= log5 (3x2) - log5 (2x3)
But that would = 0 wouldn't it? You can't express =0 into one log don't you?
Also, I found this law: log a (p/q)= (loga (p))- (loga (q))
But I don't know how to translate the original equation with that law.