#1**0 **

log_2 (x/y) = 3?

y = x/8 = (log(x/y))/(log(2)) = 3 = log(x/y) = log(8) = log((8 y)/x) = 0

Guest Mar 5, 2017

#2**+1 **

Using the change of base formula:

\(\log_{2}(x/y) = \frac{log_{10}(x/y)}{\log_{10}2} = 3 \\~\\ \log_{10}(x/y)=3(\log_{10}2) \\~\\ \log_{10}(x/y)=\log_{10}(2^3) \\~\\ x/y = 2^3 \\~\\ x/y = 8\)

So x = 8y and y = x/8

I don't know what Guest did, but I'm pretty sure y can't be zero because that would make a zero in the denominator and that would mean that it doesn't equal 3, it would just not be a true statement.

hectictar
Mar 5, 2017