log_2 (x/y) = 3?
y = x/8 = (log(x/y))/(log(2)) = 3 = log(x/y) = log(8) = log((8 y)/x) = 0
+9479 Using the change of base formula:
\(\log_{2}(x/y) = \frac{log_{10}(x/y)}{\log_{10}2} = 3 \\~\\ \log_{10}(x/y)=3(\log_{10}2) \\~\\ \log_{10}(x/y)=\log_{10}(2^3) \\~\\ x/y = 2^3 \\~\\ x/y = 8\)
So x = 8y and y = x/8
I don't know what Guest did, but I'm pretty sure y can't be zero because that would make a zero in the denominator and that would mean that it doesn't equal 3, it would just not be a true statement.
