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avatar+546 

23) log(little3)(2x)^2 exand this

 

30) log(little2)9 use the change of base formula to solve

 

44) 1/2log(little2)15-log(little5)sqrt75 use the properties of logarithims to evaluate

 Aug 15, 2014

Best Answer 

 #1
avatar+118703 
+10

23)

 log3(2x)2=2log3(2x)=2(log3(2)+log3(x))=2log3(2)+2log3(x)

 

30)

log29=log9log2    And you can finish it with a calculator.

 

44)

12log215log575=12log2(53)log5(253)1/2=log2(53)1/2log5(253)1/2=log2(51/231/2)log5(251/231/2)=log2(51/231/2)[log5(531/2)]=log251/2+log231/2[log55+log531/2]=log251/2+log231/2[1+log531/2]=log251/2+log231/22212log53=12[log25+log232log53]

 

I was working this out as I was writing the code so it is probably not the best way.

Plus i am not very happy with the answer, but this is as far as I get. 

Maybe someone esle will do something more/different.  (Are you sure the base (little) numbers were correct?)

 Aug 15, 2014
 #1
avatar+118703 
+10
Best Answer

23)

 log3(2x)2=2log3(2x)=2(log3(2)+log3(x))=2log3(2)+2log3(x)

 

30)

log29=log9log2    And you can finish it with a calculator.

 

44)

12log215log575=12log2(53)log5(253)1/2=log2(53)1/2log5(253)1/2=log2(51/231/2)log5(251/231/2)=log2(51/231/2)[log5(531/2)]=log251/2+log231/2[log55+log531/2]=log251/2+log231/2[1+log531/2]=log251/2+log231/22212log53=12[log25+log232log53]

 

I was working this out as I was writing the code so it is probably not the best way.

Plus i am not very happy with the answer, but this is as far as I get. 

Maybe someone esle will do something more/different.  (Are you sure the base (little) numbers were correct?)

Melody Aug 15, 2014
 #2
avatar+546 
0

Look at this question again. You are trying to simplify this. Maybe try simplifying by breaking 75 into 2 different numbers (15/5)

Meoldy this for you for #44

 Aug 15, 2014

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