Solve and find the domain of the equation:
\(\log_3 ((\log_{0.5}x)^2-(3\log_{0.5}x) +5)=2\)
Solve for x over the real numbers:
log(3, log_0.5^2(x) - 3 log(0.5, x) + 5) = 2
log(3, log_0.5^2(x) - 3 log(0.5, x) + 5) = log(5 + 4.32809 log(x) + 2.08137 log^2(x))/log(3):
log(5 + 4.32809 log(x) + 2.08137 log^2(x))/log(3) = 2
Multiply both sides by log(3):
log(5 + 4.32809 log(x) + 2.08137 log^2(x)) = 2 log(3)
2 log(3) = log(3^2) = log(9):
log(5 + 4.32809 log(x) + 2.08137 log^2(x)) = log(9)
Cancel logarithms by taking exp of both sides:
5 + 4.32809 log(x) + 2.08137 log^2(x) = 9
Divide both sides by 2.08137:
2.40227 + 2.07944 log(x) + log^2(x) = 4.32408
Subtract 2.40227 from both sides:
2.07944 log(x) + log^2(x) = 1.92181
Add 1.08102 to both sides:
1.08102 + 2.07944 log(x) + log^2(x) = 3.00283
Write the left hand side as a square:
(log(x) + 1.03972)^2 = 3.00283
Take the square root of both sides:
log(x) + 1.03972 = 1.73287 or log(x) + 1.03972 = -1.73287
Subtract 1.03972 from both sides:
log(x) = 0.693147 or log(x) + 1.03972 = -1.73287
Cancel logarithms by taking exp of both sides:
x = 2. or log(x) + 1.03972 = -1.73287
Subtract 1.03972 from both sides:
x = 2. or log(x) = -2.77259
Cancel logarithms by taking exp of both sides:
x = 2 or x = 0.0625
Domain:{x element R : x>0} (all positive real numbers) (assuming a function from reals to reals)