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 Nov 1, 2018
 #1
avatar+5091 
+1

\(6 = \log\left(\dfrac{I_1}{I_s}\right) \\ 8=\log\left(\dfrac{I_2}{I_s}\right) \\ 10^6=\dfrac{I_1}{I_s}\\ 10^8=\dfrac{I_2}{I_s} \\ \dfrac{I_2}{I_1} = \dfrac{10^8}{10^6} = 10^2 = 100\)

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 Nov 1, 2018
 #2
avatar+100579 
+1

M  =  log   ( I  / S)

 

In Exponential form, we have

 

10^M  = (I /S)

 

So...we have this situation

 

 

10^8  = (I8/S)    ⇒  S * 10^8   =  I8        (1)  

and

10^6  = (I6/S)  ⇒   S * 10^6  =  I6       (2)

 

So  take the ratio of  (1) / (2)    and we have

 

I8 / I6    =    S* 10^8  / S* 10^6

 

I8 / I6   =  10^8 / 10^6

 

I8 / I6  =   10^(8 - 6)

 

I8 / I6   =  10^2    =   100 times stronger

 

 

 

cool cool cool

 Nov 1, 2018

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