Newton's law of cooling:
The face of household iron cools from 125 degrees to 100 degrees in 30minutes in a room that remains at a constant temperature of 72 degree. From the calculus the temperature f(t) of the face after "t" hours of cooling is given by: f(t)=50(2)^-2t+72
A) Assuming t=0 corresponds to 1pm, approximate to the nearest hundredth of a degree the temperature of the face at 2:30pm and 3pm.
B)sketch the graph of f for 0 <="t"<=4:
