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Hi good people!,

this log problem is confusing me:

It says: write in expanded log form:

\(log{a^4 \over3^2x}\)

So, I do this:

\(loga^4-(log3^2+logx)\)

but this gives \(loga^4-log3^2-logx \)

which gives: \(4loga-2log3-logx\)

If I convert the last line back to a solve, I cannot see how I will get \(log{a^4 \over3^2x}\), again?..

Where am I going wrong?

juriemagic Nov 9, 2017

#1

#2**+1 **

Hi Melody,

well, it's this:

\(4loga-2log3-logx\)

goes to:

\(log{a^4 \over 3^2}\)

the "-logx"...how do i "see" mathematically that it is supposed to join the \(3^2\) ?

juriemagic
Nov 9, 2017

#3**+1 **

Let's reverse the process

log ( a^{4} / [ 3^{2} x ] ) =

log a^{4} - [ log (3^{2} * x) ] =

log a ^{4} - [ log 3^{2} + log x ] =

4 log a - [ 2 log 3 + log x ]

4 log a - 2 log 3 - log x

CPhill Nov 9, 2017

#4**0 **

Hi CPhil,

yes, that is the part I understand, what I do not get is how to reverse that back to the single log term?

juriemagic
Nov 10, 2017

#5

#6**+1 **

I see,

so it's a rule to take the second and third terms, should there be a "-" between them, together into a bracket, which obviously will have the "-" change to a "+"...and move on from there?..

Thanx for your time CPhill...

juriemagic
Nov 10, 2017