+1124 Hi good people!,
this log problem is confusing me:
It says: write in expanded log form:
\(log{a^4 \over3^2x}\)
So, I do this:
\(loga^4-(log3^2+logx)\)
but this gives \(loga^4-log3^2-logx \)
which gives: \(4loga-2log3-logx\)
If I convert the last line back to a solve, I cannot see how I will get \(log{a^4 \over3^2x}\), again?..
Where am I going wrong?
+1124 Hi Melody,
well, it's this:
\(4loga-2log3-logx\)
goes to:
\(log{a^4 \over 3^2}\)
the "-logx"...how do i "see" mathematically that it is supposed to join the \(3^2\) ?
+129852 Let's reverse the process
log ( a4 / [ 32 x ] ) =
log a4 - [ log (32 * x) ] =
log a 4 - [ log 32 + log x ] =
4 log a - [ 2 log 3 + log x ]
4 log a - 2 log 3 - log x
+1124 Hi CPhil,
yes, that is the part I understand, what I do not get is how to reverse that back to the single log term?
+1124 I see,
so it's a rule to take the second and third terms, should there be a "-" between them, together into a bracket, which obviously will have the "-" change to a "+"...and move on from there?..
Thanx for your time CPhill...
