+1124 Hi good people!,
this log problem is confusing me:
It says: write in expanded log form:
loga432x
So, I do this:
loga4−(log32+logx)
but this gives loga4−log32−logx
which gives: 4loga−2log3−logx
If I convert the last line back to a solve, I cannot see how I will get loga432x, again?..
Where am I going wrong?
+1124 Hi Melody,
well, it's this:
4loga−2log3−logx
goes to:
loga432
the "-logx"...how do i "see" mathematically that it is supposed to join the 32 ?
+130474 Let's reverse the process
log ( a4 / [ 32 x ] ) =
log a4 - [ log (32 * x) ] =
log a 4 - [ log 32 + log x ] =
4 log a - [ 2 log 3 + log x ]
4 log a - 2 log 3 - log x
+1124 Hi CPhil,
yes, that is the part I understand, what I do not get is how to reverse that back to the single log term?
+1124 I see,
so it's a rule to take the second and third terms, should there be a "-" between them, together into a bracket, which obviously will have the "-" change to a "+"...and move on from there?..
Thanx for your time CPhill...
