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# logy x=3 logy (4x)=5

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logy x=3 logy (4x)=5

Guest Sep 25, 2014

#1
+19062
+5

logy x=3 logy (4x)=5

$$\small{\text{  \begin{array}{rclc|rclc} \log_y{ (x) } & = & 3 & | \quad y^{()} \quad & \quad \log_y {(4x)} & = & 5 \quad | \quad y^{()} \\ y^{\log_y{ (x) }} & = & y^3 & \quad & \quad y^{\log_y {(4x)}} & = &y^5 \\ x & = & y^3 & \quad & \quad 4x & = & y^5 \\ & & & & 4y^3 & = & y^5 \quad | \quad :y^3 \\ & & & & 4 & = & y^2 \quad | \quad \sqrt \\ & & & & 2 & = & y \\ x & = & 2^3 & & y & = & 2 \\ x & = & 8 & & y & = & 2 \\ \end{array}  }}$$

$$\small{\text{  \log_2{(8)}=3 \qquad \log_2{(4*8)}=5  }}$$

heureka  Sep 26, 2014
Sort:

#1
+19062
+5

logy x=3 logy (4x)=5

$$\small{\text{  \begin{array}{rclc|rclc} \log_y{ (x) } & = & 3 & | \quad y^{()} \quad & \quad \log_y {(4x)} & = & 5 \quad | \quad y^{()} \\ y^{\log_y{ (x) }} & = & y^3 & \quad & \quad y^{\log_y {(4x)}} & = &y^5 \\ x & = & y^3 & \quad & \quad 4x & = & y^5 \\ & & & & 4y^3 & = & y^5 \quad | \quad :y^3 \\ & & & & 4 & = & y^2 \quad | \quad \sqrt \\ & & & & 2 & = & y \\ x & = & 2^3 & & y & = & 2 \\ x & = & 8 & & y & = & 2 \\ \end{array}  }}$$

$$\small{\text{  \log_2{(8)}=3 \qquad \log_2{(4*8)}=5  }}$$

heureka  Sep 26, 2014
#2
+91919
+3

Nice one Heureka,

I didn't even realise that I was being presented with 2 equations to solve simultaneously!

I didn't understand WHAT the question was.  Perhaps you could present it a little better next time anonymous.

Heureka may not be around to interprete!

Anyway, that is a really nice solution Heureka.

Melody  Sep 26, 2014

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