+99 see image
What is the equation of this circle in general form? answer choices below image
x2+y2−6x+4=0
x2+y2−6x−16=0
x2+y2+6x−16=0
x² + y² + 6x + 4 = 0
+9479 From looking at the graph, we can see that
the center of this circle is the point (3, 0) and
the radius of this circle is 5 units.
So, the equation of this circle in standard form is:
(x - 3)2 + (y - 0)2 = 52 Simplified, this is....
(x - 3)2 + y2 = 25
To get this equation in general form, first multiply out the (x - 3)2 .
(x - 3)(x - 3) + y2 = 25
x2 - 3x - 3x + 9 + y2 = 25 Subtract 25 from both sides of the equation.
x2 - 3x - 3x + 9 + y2 - 25 = 0 Combine like terms and rearrange.
x2 + y2 - 6x - 16 = 0
+9479 From looking at the graph, we can see that
the center of this circle is the point (3, 0) and
the radius of this circle is 5 units.
So, the equation of this circle in standard form is:
(x - 3)2 + (y - 0)2 = 52 Simplified, this is....
(x - 3)2 + y2 = 25
To get this equation in general form, first multiply out the (x - 3)2 .
(x - 3)(x - 3) + y2 = 25
x2 - 3x - 3x + 9 + y2 = 25 Subtract 25 from both sides of the equation.
x2 - 3x - 3x + 9 + y2 - 25 = 0 Combine like terms and rearrange.
x2 + y2 - 6x - 16 = 0
