+0  
 
0
787
3
avatar

m=(-6,-1)n=(-1,-7) what is the distance between M and N on an xy table?

 Jul 7, 2014

Best Answer 

 #1
avatar+576 
+8

Think of this as a pythagorean theorem problem where on a right triangle where one leg is the distance between the x coordinates, another is the distance between the y coordinates, and the total distance is the hypotenuse.

(-6-(-1))^2+(-1-(-7))^2 =d^2

5^2 +6^2=d^2

25+36=d^2

d=sqrt(61)=7.8

 Jul 7, 2014
 #1
avatar+576 
+8
Best Answer

Think of this as a pythagorean theorem problem where on a right triangle where one leg is the distance between the x coordinates, another is the distance between the y coordinates, and the total distance is the hypotenuse.

(-6-(-1))^2+(-1-(-7))^2 =d^2

5^2 +6^2=d^2

25+36=d^2

d=sqrt(61)=7.8

jboy314 Jul 7, 2014
 #2
avatar+33661 
+5

The x-values differ by 5 and the y-values differ by 6, so using Pythagoras's theorem the distance between M and N is √(52 + 62)

$${\sqrt{{{\mathtt{5}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{6}}}^{{\mathtt{2}}}}} = {\mathtt{7.810\: \!249\: \!675\: \!906\: \!654\: \!4}}$$

 Jul 7, 2014
 #3
avatar+129852 
+5

First, subtract the x values..so we have...(-1-(-6)) = (5)

Next...subtract the y values  (-1-(-7)) = (6)

Square both of these and add the results together.......so we have

(5)^2 + (6)^2   =  25 + 36 = 61

Take the sqaure root of this = √(61)

And there is the distance between the two points !!!

 

  

 Jul 7, 2014

5 Online Users

avatar
avatar
avatar
avatar