+576 Think of this as a pythagorean theorem problem where on a right triangle where one leg is the distance between the x coordinates, another is the distance between the y coordinates, and the total distance is the hypotenuse.
(-6-(-1))^2+(-1-(-7))^2 =d^2
5^2 +6^2=d^2
25+36=d^2
d=sqrt(61)=7.8
+576 Think of this as a pythagorean theorem problem where on a right triangle where one leg is the distance between the x coordinates, another is the distance between the y coordinates, and the total distance is the hypotenuse.
(-6-(-1))^2+(-1-(-7))^2 =d^2
5^2 +6^2=d^2
25+36=d^2
d=sqrt(61)=7.8
+33615 The x-values differ by 5 and the y-values differ by 6, so using Pythagoras's theorem the distance between M and N is √(52 + 62)
$${\sqrt{{{\mathtt{5}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{6}}}^{{\mathtt{2}}}}} = {\mathtt{7.810\: \!249\: \!675\: \!906\: \!654\: \!4}}$$
+128472 First, subtract the x values..so we have...(-1-(-6)) = (5)
Next...subtract the y values (-1-(-7)) = (6)
Square both of these and add the results together.......so we have
(5)^2 + (6)^2 = 25 + 36 = 61
Take the sqaure root of this = √(61)
And there is the distance between the two points !!!
