+1995 What is the magnitude of normal force acting on the block when it is resting on the flat surface? How does the normal force change as the angle of the ramp increases? Explain. (Assume that the ramps are frictionless surfaces.)
I think I would need to use tetra? ( this is what i thought . The normal force is determined through N=mgcos θ . When the surface is resting on a flat surface, θ= 90 N = mgcos(0) = 0. ) but i think i may be wrng and need to use tetra?
+37146 Normal force is the force acting perpindicular to the plane (ramp) and would be mg cos theta where theta is the angle of the ramp. at 0 degrees cos theta = 1 as the ramp angle is increased cos theta gets smaller and the normal force decreases to 0 at theta = 90 degrees.
+37146 The magnitude is the 'amount' ... the force is mg cos theta that is the magnitude......
