If a ball is thrown directly upward with a velocity of 44 ft/s, its height (in feet) after t seconds is given by y = 44t − 16t^2. What is the maximum height attained by the ball? (Round your answer to the nearest whole number.)
The 16t is squared by 2
+10 I am pretty sure all you have to do is to find an integer for t that maximizes y and solve for it.
+36916 -b/2a = - 44/-32 = 1.375 =t
44 (1.375) -16(1.375)^2 = max height
