We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
68
4
avatar

If a ball is thrown directly upward with a velocity of 44 ft/s, its height (in feet) after t seconds is given by y = 44t − 16t^2. What is the maximum height attained by the ball? (Round your answer to the nearest whole number.)

 

The 16t is squared by 2

 Oct 11, 2019
edited by Guest  Oct 11, 2019
 #1
avatar+10 
+3

I am pretty sure all you have to do is to find an integer for t that maximizes y and solve for it.

cheekycheeky

 Oct 11, 2019
 #2
avatar+10 
+2

Also, does the variable y mean the distance attained by the ball?

 Oct 11, 2019
 #4
avatar+19697 
+2

yes, 'y' is the height at time t

ElectricPavlov  Oct 11, 2019
 #3
avatar+19697 
+3

-b/2a  =  - 44/-32 = 1.375  =t

 

44 (1.375) -16(1.375)^2  = max height

 Oct 11, 2019
edited by Guest  Oct 11, 2019

23 Online Users

avatar
avatar
avatar