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If a ball is thrown directly upward with a velocity of 44 ft/s, its height (in feet) after t seconds is given by y = 44t − 16t^2. What is the maximum height attained by the ball? (Round your answer to the nearest whole number.)

 

The 16t is squared by 2

 Oct 11, 2019
edited by Guest  Oct 11, 2019
 #1
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+3

I am pretty sure all you have to do is to find an integer for t that maximizes y and solve for it.

cheekycheeky

 Oct 11, 2019
 #2
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+2

Also, does the variable y mean the distance attained by the ball?

 Oct 11, 2019
 #4
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yes, 'y' is the height at time t

ElectricPavlov  Oct 11, 2019
 #3
avatar+19950 
0

-b/2a  =  - 44/-32 = 1.375  =t

 

44 (1.375) -16(1.375)^2  = max height

 Oct 11, 2019
edited by Guest  Oct 11, 2019

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