+208 Find the following using the given functions . ( Simplify your answers completely.)
f ( x) = 6x3 − x2 + 4x + 5 and g ( x) = 9x3 − 1
a. ( f + g ) (x) =
(b)
( f + g ) (2) =
(c)
( f − g ) (x) =
(d)
( f − g ) (−3) =
+934 a. (f+g)(x)= 6x^3-x^2+4x+5+9x^3-1= 15x^3-x^2+4x+4
b. (f+g)(2)= 15 * 2^3 - 2^2 + 4 * 2 + 4= 128
c. (f-g)(x)= 6x^3-x^2+4x+5-9x^3-1= -3x^3-x^2+4x+6
d. (f-g)(-3)= -3 * (-3)^3 - (-3)^2 + 4 * (-3) + 6= 66.
Hope it helps!
