+349 Last time, I gave you guys this problem:
\(X^{X^{X^{X^{X...}}}}=3 \)
What is the value of X?
The answer is \(\sqrt[3]{3}\)
Why? Well, let's look at this closely:
If X3 = 3, then X = \(\sqrt[3]{3}\)
If \(X^{X^3}=3,\)
Then X = \(\sqrt[3]{3}\)
because X3 then would be 3, and X3 = 3, so \(X^{X^3}=3,\)
Now, if \(X^{X^{X^{X^{X...}}}}=3 \)
Then X = the cube root of three. Since there is no end "three" to X raised to the power of X, we can immediately conclude that \(X=\sqrt[3]{3}\)
That's it. Bye. 
