fracrem: (3^(1/2))sinx-cosx = 2sin(x-30)
Find all values of x in the range 0<=x<=360 which satisfy the equation 4sinxcosx = (3^(1/2))sinx-cosx
One simple way to do this would be to run through the values of x from 0 to 360 (do it in steps of 10 degrees at a time) and see which make both sides equal (it works ok here because the solutions are whole numbers of degrees!).
Or look at the graph below:
angles.PNG
+33616 
