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Nella travelled 1/3 of a journey by bus, 2/3 of the remainder by bicycle and the remaining 9km on foot. (a) how far did nella cycle (b) what was the total distance travel

 Mar 10, 2016
 #1
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Nella travelled 1/3 of a journey by bus, 2/3 of the remainder by bicycle and the remaining 9km on foot.

 

j = journey

c = cycle

b = bus

 

 

(a) how far did nella cycle

\(\begin{array}{lrcll} (1) & c &=& (\frac23\cdot j) \cdot \frac23 \\ & \frac23\cdot j &=& \frac32\cdot c \\\\ (2) & c + 9\ \text{km} &=& \frac23 \cdot j \\ & c + 9\ \text{km} &=& \frac32\cdot c \\ & \frac32\cdot c - c &=& 9 \\ & \frac12\cdot c &=& 9 \\ & c &=& 18\ \text{km}\\ \end{array}\)

 

Nella cycle 18 km

 

(b) what was the total distance travel

\(\begin{array}{lrcll} & \frac23\cdot j &=& \frac32\cdot c \\ & j &=& \frac32\cdot \frac32\cdot c \\ & j &=& \frac32\cdot \frac32\cdot 18\ \text{km} \\ & j &=& 40.5\ \text{km} \end{array}\)

 

The total distance travel was 40.5 km

 

\(\begin{array}{rcll} b &=& \frac13 \cdot j \\ b &=& \frac13 \cdot 40.5\ \text{km} \\ b &=& 13.5\ \text{km} \\ \end{array}\)

 

laugh

 Mar 10, 2016
 #2
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Let the total distance be =D

1/3D.2/3D =9

2/9D=9

D=9.9/2

D=40.5 Km. Total diseance

40.5 1/3=13.5 Km by bus

27.2/3 =18 Km by cycle

9 Km by foot.

 Mar 10, 2016

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