#1**-3 **

You are given the y-interecept -2 which is also written as (0, -2)

Because we know the slope and a point we can use the point-slope formula to write and equation for the line. The point-slope formula states: (y−y1) = m(x−x1)

Where m is the slope and (x1,y1) is a point the line passes through.

Substituting the slope and the values from the point in the problem gives:

\((y--2) = 3(x-0)\)

\((y+2)=3(x-0)\)

The slope-intercept form of a linear equation is: y=mx+b

\(y + 2= (3*x)+(3*0)\)

\(y+2=3x+0\)

\(y+2-2=3x+0-2\)

\(y=3x-2\)

Then write it in standard form:

\(y=3x-2\)

\(y+2=3x-2+2\)

\(y+2=3x\)

\(y+2-y=3x-y\)

\(2=3x-y\)

Your standard form is 2

EmeraldWonder Jun 3, 2019

#2**-1 **

Thanks Ik the slope intercept form but I don't know how i would put it in standard form. I need standard form

kingJay Jun 3, 2019