+219 You are given the y-interecept -2 which is also written as (0, -2)
Because we know the slope and a point we can use the point-slope formula to write and equation for the line. The point-slope formula states: (y−y1) = m(x−x1)
Where m is the slope and (x1,y1) is a point the line passes through.
Substituting the slope and the values from the point in the problem gives:
\((y--2) = 3(x-0)\)
\((y+2)=3(x-0)\)
The slope-intercept form of a linear equation is: y=mx+b
\(y + 2= (3*x)+(3*0)\)
\(y+2=3x+0\)
\(y+2-2=3x+0-2\)
\(y=3x-2\)
Then write it in standard form:
\(y=3x-2\)
\(y+2=3x-2+2\)
\(y+2=3x\)
\(y+2-y=3x-y\)
\(2=3x-y\)
Your standard form is 2
+46 Thanks Ik the slope intercept form but I don't know how i would put it in standard form. I need standard form
How would i write this in standard form??
