+0  
 
0
49
1
avatar+187 

Consider four 1x1 squares as shown to get the five pieces above known as tetrominoes. Place
these five tetrominoes inside a rectangle so the pieces do not overlap, and the sides of the
pieces are on or are parallel to sides of the rectangle. If the sides of the rectangle have integer
lengths, what is the least possible area of the rectangle?

 Sep 16, 2021
 #1
avatar
0

The total area of the pieces is 4*5 = 20, so the smallest possible area of the rectangle is 20.

 Sep 16, 2021

10 Online Users

avatar
avatar