Let P (n) denote the number of factors of n. Find all values of n which satisfy
\(P(n)^2 =n\)
and justify your solution.
I think it means like the following Melody:
Consider n = 9. The factors of 9 are 1, 3 and 9. That is, there are three factors, so P(9) = 3, which means P(9)^2 = 9.
On the other hand the factors of 6 are 1, 2, 3 and 6 so P(6) = 4, hence P(6)^2 > 6
The question is asking for all the values of n that are like my first example (I think!).