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Guest Dec 18, 2014

#1
+17721
+5

Let                                                     log√5125√5  =  x

Then write this into exponential notation:       √5x  =  125√5

Now, I want to write 125 with a base of √5:

---  first,  125  =  53

---  also,  (√5)2  =  5

---  so:    125  =   53  =  [ (√5)2 ]3  = (√5)6

---  and:  125√5  =  (√5)6 ·√5  =  (√5)7

Thus:   √5x  =  (√5)7     --->  x = 7

geno3141  Dec 18, 2014
Sort:

#1
+17721
+5

Let                                                     log√5125√5  =  x

Then write this into exponential notation:       √5x  =  125√5

Now, I want to write 125 with a base of √5:

---  first,  125  =  53

---  also,  (√5)2  =  5

---  so:    125  =   53  =  [ (√5)2 ]3  = (√5)6

---  and:  125√5  =  (√5)6 ·√5  =  (√5)7

Thus:   √5x  =  (√5)7     --->  x = 7

geno3141  Dec 18, 2014

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