Hi, my name is Tori! I need help with this problem. Could you help me please. I am not sure what to do.
The depth d in feet of the water in a bay at is given by d(t) = 3/2 sin (5πt/31) + 23 where t is time. Graph the depth of the water as a function of time. What is the maximum depth of the water to the nearest tenth of a foot? (Enter only the number.)
+118677 d(t) = 3/2 sin (5πt/31) + 23
The average depth of the water, over time, is 23 feet.
The amplitue of the tide is 1.5 feet
So the maximum depth of the water is 24.5m
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You do not need this but the period is 2pi divided by 5pi/31 = 2pi*31/5pi = 62/5 = 12.4
I think it fair to assume that we are talking tides and time is in hours.
+98 A plot of
from 0 through 3 pi is attached.
dose this help
+129852 The max depth of the water is 24.5 ft.
Here's the graph here (you may have to scroll "up" on the Desmos webpage to see it).......https://www.desmos.com/calculator/ukrmefrp28
(Note ...I have graphed it using "x" and "y" instead of "t" and "d" ....but the idea is the same !!!)
+118677 d(t) = 3/2 sin (5πt/31) + 23
The average depth of the water, over time, is 23 feet.
The amplitue of the tide is 1.5 feet
So the maximum depth of the water is 24.5m
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You do not need this but the period is 2pi divided by 5pi/31 = 2pi*31/5pi = 62/5 = 12.4
I think it fair to assume that we are talking tides and time is in hours.
