+70
Fill in the blanks with integers, and select the correct operator ( + or -), to give an equation whose graph is the line that passes through the point (-7, 2) and is parallel to the graph of 2x+3y = -5.
__x ? __y = __
please help
The slope of the line 2x+3y = -5 is 2/3. So, the equation of our parallel line will be of the form y = (2/3)x + b, where b is the y-intercept.
We know that the line passes through the point (-7, 2), so we can plug these values into the equation to solve for b. This gives us:
2 = (2/3)(-7) + b 2 = -14/3 + b 2 + 14/3 = b = 10/3
Therefore, the equation of the parallel line is y = (2/3)x + (10/3). Filling in the blanks, we get:
2x ? + y = 10
The answer is 2x + y = 10.
The slope of the line 2x+3y = -5 is -2/3. Since the parallel line has the same slope, the equation of the parallel line will be of the form 2x - 3y = b.
We know that the parallel line passes through the point (-7, 2), so we can plug these values into the equation to solve for b. This gives us:
2 * -7 - 3 * 2 = b -14 - 6 = b -20 = b
Therefore, the equation of the parallel line is 2x - 3y = -20.
The operator that should be used is -.
