Use technology or a z-distribution table to find the indicated area.
Suppose ages of cars driven by company employees are normally distributed with a mean of 8 years and a standard deviation of 3.2 years.
Approximately 75% of cars driven by company employees are older than what age?
2.1
4.8
5.9
10.2
+37159 Using a z-score table, +.67 SD is 74.86 percent and +.68 SD is 75.17 % of all the cars I'll just use .674 SD
.674 x SD = .674 x 3.2 = 2.157 yrs
Add this to the median 8 + 2.157 = 10.157 yrs ~~ 10.2 yrs.
