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avatar+206 

Simplify and state any restrictions on the variables.5y/Z-2y^2/3z^5

 

A bit confused about this. I understand that the restriction is that x can't = zero but the simplifying part is what gets me.

Julius  Mar 5, 2017

Best Answer 

 #2
avatar+4161 
+11

\(\frac{5y}{z}-\frac{2y^2}{3z^5} \\ \text{If z is 0 then the problem is undefined. So z ≠ 0.} \\ \frac{5y(3z^4)}{z(3z^4)}-\frac{2y^2}{3z^5} \\ \frac{15yz^4-2y^2}{3z^5}\)

 

As far as I can tell that is it in the simplest form, and the only restriction is z ≠ 0.

 

That is what I got but I don't really know what the definition of "simple" is sometimes.

hectictar  Mar 5, 2017
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3+0 Answers

 #1
avatar+206 
+5

Does it simplify to:15yz^4-2y^2/3z^5?

Julius  Mar 5, 2017
 #2
avatar+4161 
+11
Best Answer

\(\frac{5y}{z}-\frac{2y^2}{3z^5} \\ \text{If z is 0 then the problem is undefined. So z ≠ 0.} \\ \frac{5y(3z^4)}{z(3z^4)}-\frac{2y^2}{3z^5} \\ \frac{15yz^4-2y^2}{3z^5}\)

 

As far as I can tell that is it in the simplest form, and the only restriction is z ≠ 0.

 

That is what I got but I don't really know what the definition of "simple" is sometimes.

hectictar  Mar 5, 2017
 #3
avatar+206 
+10

Okay that makes sense. Thanks :)

Julius  Mar 5, 2017

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