+0

# Math help

0
78
3
+214

Simplify and state any restrictions on the variables.5y/Z-2y^2/3z^5

A bit confused about this. I understand that the restriction is that x can't = zero but the simplifying part is what gets me.

Julius  Mar 5, 2017

#2
+4777
+11

$$\frac{5y}{z}-\frac{2y^2}{3z^5} \\ \text{If z is 0 then the problem is undefined. So z ≠ 0.} \\ \frac{5y(3z^4)}{z(3z^4)}-\frac{2y^2}{3z^5} \\ \frac{15yz^4-2y^2}{3z^5}$$

As far as I can tell that is it in the simplest form, and the only restriction is z ≠ 0.

That is what I got but I don't really know what the definition of "simple" is sometimes.

hectictar  Mar 5, 2017
Sort:

#1
+214
+5

Does it simplify to:15yz^4-2y^2/3z^5?

Julius  Mar 5, 2017
#2
+4777
+11

$$\frac{5y}{z}-\frac{2y^2}{3z^5} \\ \text{If z is 0 then the problem is undefined. So z ≠ 0.} \\ \frac{5y(3z^4)}{z(3z^4)}-\frac{2y^2}{3z^5} \\ \frac{15yz^4-2y^2}{3z^5}$$

As far as I can tell that is it in the simplest form, and the only restriction is z ≠ 0.

That is what I got but I don't really know what the definition of "simple" is sometimes.

hectictar  Mar 5, 2017
#3
+214
+10

Okay that makes sense. Thanks :)

Julius  Mar 5, 2017

### 21 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details