Math help

Okay.

Then, you do the same for the constants. I'll be adding 3/5 to each side.

1 14/15-1=4/15x

Then, solve the left side.

14/15=4/15x

Multiply by 15 on both sides.

14=4x

Then, divide by 4 on each side.

3.5=x

In conclusion, x=3.5 or 3 and a half. Hope I helped, but sorry if my math is off. I had to hurry a bit.

I'll get you stated....see if you can finish!

1/3  (x+4)  - 1  =  3/5  (x-1)

1/3x  + 4/3 -1  =   3/5 x  -  3/5           I would start by doing the 4/3-1 part and then   add  3/5 to both sides....try it...see what you find!

I like what guest did, but let me make this a bit clearer.

1/3(x+4)-1=3/5(x-1) is what you have.

First, distribute.

(1/3*x+1/3*4)-1=3/5*x-3/5*1

What you get is...

(1/3x+1 1/3)-1=3/5x-3/5

Then, add/subtract an equal amount of x from each side. In this example, I will be subtracting 1/3 from both sides.

1 1/3-1=4/15x-3/5

I'm at my character limit, so I'll be posting the rest in a separate post.

Yes that is a good idea thanks guest.

Another way is to multiply both sides by the smallest common denominator which is 15

\(\frac{x+4}{3}-1=\frac{3(x-1)}{5}\\ \frac{x+4}{3}-\frac{3}{3}=\frac{3(x-1)}{5}\\ \frac{x+4-3}{3}=\frac{3(x-1)}{5}\\ \frac{x+1}{3}=\frac{3(x-1)}{5}\\ \frac{15}{1}\times\frac{x+1}{3}=\frac{15}{1}\times\frac{3(x-1)}{5}\\ \frac{5}{1}\times\frac{x+1}{1}=\frac{3}{1}\times\frac{3(x-1)}{1}\\ 5(x+1)=9(x-1)\\ \)

and you can check and finish :)

Excellent work annonymous 4338     

It is great to see you back on the forum :)

Thanks! The forum's changed a bunch since I've last been on, but I'm planning to be more active this week since I have no school. Anyhow, it's getting pretty late for me now, soo I think I'll be going now. It's great seeing you again.