The circumradius of a triangle with sides of lengths a, b, and c is given by the formula
R = \frac{abc}{4\sqrt{(s)(s - a)(s - b)(s - c)}}
where s is the semiperimeter of the triangle, s = (a + b + c) / 2.
In this case, the sides of the triangle are 29, 29, and 42, so the semiperimeter is s = (29 + 29 + 42) / 2 = 49. The area of the triangle is then
A = \sqrt{s(s - a)(s - b)(s - c)} = \sqrt{49(49 - 29)(49 - 29)(49 - 42)} = 420
Therefore, the circumradius is
R = \frac{abc}{4A} = \frac{(29)(29)(42)}{4(420)} = \frac{29}{6}
