When a skydiver jumps from an airplane, her downward velocity, in feet per second, before she opens her parachute is given by the formula below, where t is the number of seconds that have elapsed since she jumped from the airplane.
The terminal velocity for the skydiver is 180 feet per second. v = 180(1 − 0.834^t)
Q: How long does it take to reach 65% of the terminal velocity? (Round your answer to two decimal places.)
v = 180(1 − 0.834^t)
Q: How long does it take to reach 65% of the terminal velocity? (Round your answer to two decimal places.)
65% of the termiinal velocity is: .65 X 180=117, then we have,
117=180(1 - .834^t), solving for t we get,
t=5.78 seconds - the time to reach 65% of terminal velocity.
v = 180(1 − 0.834^t)
Q: How long does it take to reach 65% of the terminal velocity? (Round your answer to two decimal places.)
65% of the termiinal velocity is: .65 X 180=117, then we have,
117=180(1 - .834^t), solving for t we get,
t=5.78 seconds - the time to reach 65% of terminal velocity.
