+67 The product \((3-\sqrt{5})(4+2\sqrt{5})\) can be expressed in the form \(a+b\sqrt{5}\), where a and b are integers. Find a+b.
+526 \((3-\sqrt5)(4+2\sqrt5) = 12-4\sqrt5+6\sqrt5-2(5)\)
\(=2+2\sqrt5\)
\(a+b\sqrt5= 2+2\sqrt5\)
Comparing both sides,
\(a= 2\) and \(b=2\)
\(a+b=4\)
~I hope its clear now :)
