if you have a 18 foot diameter circular above dround pool that is $48.43 what is the cost per square foot of this cover?

Guest Mar 18, 2017

#1**+2 **

How many "square feet" are in the pool cover?

area = π * radius^{2}

radius = diameter / 2

radius = 18 feet / 2

radius = 9 feet

area = π * (9 feet)^{2}

area = 81π square feet

So there are 81π square feet in the pool cover.

...

Now let me ask this...

If there are 2 apples in a basket,

and the total cost of the basket is $6,

how much does each apple cost individually?

$6 / 2 apples = $3 per apple

...

If there are 81π square feet in the pool cover,

and the total cost of the pool cover is $48.43,

how much does each square foot cost?

$48.43 / (81π) square feet ≈ $0.19 per square foot *thx EP

hectictar
Mar 19, 2017

#2**+1 **

radius = 9 area = pi x r^2 = 81pi sq ft

$48.43/ (81 pi) = .1903 ~~~ 19 cents per sq ft

ElectricPavlov
Mar 19, 2017