+0

# Math I need help!!

0
128
2

You have four tiles that say M, A, T, and H. How many words can you form from these tiles? For example, you can form "AMH" and "TH". (The words do not have to be valid English words.)

Guest Apr 30, 2018
#1
+963
+3

Case 1: 1 letter word

There are 4 ways to do this.

Case 2: 2 letter word

There are  $$4\cdot3$$ , ways to do this.

Case 3: 3 letter word

There are $$4\cdot3\cdot2=24$$, ways to do this.

Case 4: 4 letter word

There are $$4!=24$$, ways to do this.

Add them all up, 4 + 12 + 24 + 24 = 64

I hope this helped,

Gavin

GYanggg  Apr 30, 2018
edited by GYanggg  Apr 30, 2018
#2
+2

I think the question is about "Permutations" where "order" is important, an not "Combinations" where "order" doesn't matter.

4P1 = 4 one-letter words.

4P2 =12 two-letter words.

4P3=24 three-letter words.

4P4 =4! =24 four-letter words.

Total =4 + 12 + 24 + 24 = 64 words.

Guest Apr 30, 2018