The length of one side a triangular lot is 6 m less than three times the length of the second side. The third side is 8 m longer than the first side. The perimeter of the lot is 80m. Find the length of all three sides.
+128517 Let the second side = x
The first side is 3x - 6
The third side is (3x - 6) + 8 = 3x + 2 and we have
(3x - 6) + (x) + (3x + 2) = 80 simplify
7x - 4 = 80 add 4 to both sides
7x = 84 divide both sides by 7
x = 12m this is the second side
(3(12) - 6) = (36 - 6) = 30m this is the first side
(3(12) + 2) = (36 + 2) = 38m this is the third side
