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A math problem that could be solved?

 Mar 2, 2019
edited by GAMEMASTERX40  Mar 2, 2019
 #1
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+1

 

From the information about the first balloon, we can determine k 

 

k = V1/T1 = 600/285 = 2.1053 (this is rounded from 2.10526316)

 

Since k has now been determined, it's just arithmetic to solve for the second and third balloons.

 

k = V2/T2 

2.1053 = 630/T2

(2.1053)T2 = 630

T2 = 630/2.1053 = 299.24

 

You can use this same method to solve for V3

 

 

.

 Mar 2, 2019
 #2
avatar+18449 
+3

Ideal gas law  is  PV =nRT      since n is constant (# moles) for this experiment, we can say PV = kT

and then   P/k = T/V       Pressure in the balloon is constant for all three balloons    so we can say that for all three balloons  P/k is constant  

So initially

k = T/V    =

 

V1/T1 = 600/285 =2.11=k    for all of the balloons

 

Now for the second balloon ' k ' has to be the same

630/T2 =2.11   T2 = 298.6 Kelvin

 

For balloon 3

k = 2.11    = V3/T3 = V3/265    yields   V3 = 559 ml    

 Mar 2, 2019

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