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#1**+1 **

From the information about the first balloon, we can determine k

k = V_{1}/T_{1} = 600/285 = 2**.**1053 (this is rounded from 2**.**10526316)

Since k has now been determined, it's just arithmetic to solve for the second and third balloons.

k = V_{2}/T_{2}

2**.**1053 = 630/T_{2}

(2**.**1053)T_{2} = 630

T_{2} = 630/2**.**1053 = 299**.**24

You can use this same method to solve for V_{3}

.

Guest Mar 2, 2019

#2**+3 **

Ideal gas law is PV =nRT since n is constant (# moles) for this experiment, we can say PV = kT

and then P/k = T/V Pressure in the balloon is constant for all three balloons so we can say that for all three balloons P/k is constant

So initially

k = T/V =

V_{1}/T_{1 = 600/285 =2.11=k for all of the balloons}

_{Now for the second balloon ' k ' has to be the same}

_{630/T2 =2.11 T}_{2 = 298.6 Kelvin}

_{For balloon 3 }

_{k = 2.11 = V3/T3 = V3/265 yields V3 = 559 ml }

ElectricPavlov Mar 2, 2019