From the information about the first balloon, we can determine k
k = V1/T1 = 600/285 = 2.1053 (this is rounded from 2.10526316)
Since k has now been determined, it's just arithmetic to solve for the second and third balloons.
k = V2/T2
2.1053 = 630/T2
(2.1053)T2 = 630
T2 = 630/2.1053 = 299.24
You can use this same method to solve for V3
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Ideal gas law is PV =nRT since n is constant (# moles) for this experiment, we can say PV = kT
and then P/k = T/V Pressure in the balloon is constant for all three balloons so we can say that for all three balloons P/k is constant
So initially
k = T/V =
V1/T1 = 600/285 =2.11=k for all of the balloons
Now for the second balloon ' k ' has to be the same
630/T2 =2.11 T2 = 298.6 Kelvin
For balloon 3
k = 2.11 = V3/T3 = V3/265 yields V3 = 559 ml